Introduction

When $a \ne 0$, there are two solutions to $(ax^2 + bx + c = 0)$ and they are $x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$

When $a \ne 0$, there are two solutions to $(ax^2 + bx + c = 0)$ and they are $x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$